毕设判题测试样例

AC

两数之和

import java.util.*;

public class Main {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);

        // 输入数组长度
        int n = sc.nextInt();
        int[] nums = new int[n];

        // 输入目标值
        int target = sc.nextInt();
        // 输入数组元素
        for (int i = 0; i < n; i++) {
            nums[i] = sc.nextInt();
        }

        // 调用解法
        int[] result = twoSum(nums, target);

        // 输出为数组格式：[0,1]
        System.out.println(Arrays.toString(result));

    }

    public static int[] twoSum(int[] nums, int target) {
        Map<Integer, Integer> map = new HashMap<>();
        for (int i = 0; i < nums.length; i++) {
            int need = target - nums[i];
            if (map.containsKey(need)) {
                return new int[]{map.get(need), i};
            }
            map.put(nums[i], i);
        }
        return null;
    }
}

回文数

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        int x = scanner.nextInt();
        System.out.println(isPalindrome(x));
    }

    public static boolean isPalindrome(int x) {
        // 负数一定不是回文数，且以0结尾的数（除0本身）也不是回文数
        if (x < 0 || (x % 10 == 0 && x != 0)) return false;

        int reversed = 0;
        while (x > reversed) {
            reversed = reversed * 10 + x % 10;
            x /= 10;
        }

        // x == reversed 是偶数长度，x == reversed/10 是奇数长度
        return x == reversed || x == reversed / 10;
    }
}

#include <iostream>
using namespace std;

bool isPalindrome(int x) {
    if (x < 0 || (x % 10 == 0 && x != 0)) return false;

    int reverted = 0;
    while (x > reverted) {
        reverted = reverted * 10 + x % 10;
        x /= 10;
    }

    return x == reverted || x == reverted / 10;
}

int main() {
    int x;
    cin >> x;
    cout << (isPalindrome(x) ? "true" : "false") << endl;
    return 0;
}

def is_palindrome(x: int) -> bool:
    if x < 0:
        return False
    return str(x) == str(x)[::-1]

if __name__ == "__main__":
    x = int(input())
    print("true" if is_palindrome(x) else "false")